1311242365403 has 2 divisors, whose sum is σ = 1311242365404. Its totient is φ = 1311242365402.

The previous prime is 1311242365351. The next prime is 1311242365409. The reversal of 1311242365403 is 3045632421131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1311242365403 - 2¹² = 1311242361307 is a prime.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (1311242365409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655621182701 + 655621182702.

It is an arithmetic number, because the mean of its divisors is an integer number (655621182702).

Almost surely, 2^{1311242365403} is an apocalyptic number.

1311242365403 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311242365403 is an equidigital number, since it uses as much as digits as its factorization.

1311242365403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 35.

Adding to 1311242365403 its reverse (3045632421131), we get a palindrome (4356874786534).

The spelling of 1311242365403 in words is "one trillion, three hundred eleven billion, two hundred forty-two million, three hundred sixty-five thousand, four hundred three".