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1311242365409 is a prime number
BaseRepresentation
bin10011000101001100001…
…000101010100111100001
311122100112201211210022012
4103011030020222213201
5132440411021143114
62442213150322305
7163506544131044
oct23051410524741
94570481753265
101311242365409
11466105149779
121921644b9395
139685a2c0472
1447670708c5b
1524195ddb63e
hex1314c22a9e1

1311242365409 has 2 divisors, whose sum is σ = 1311242365410. Its totient is φ = 1311242365408.

The previous prime is 1311242365403. The next prime is 1311242365439. The reversal of 1311242365409 is 9045632421131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 858485637025 + 452756728384 = 926545^2 + 672872^2 .

It is an emirp because it is prime and its reverse (9045632421131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1311242365409 is a prime.

It is not a weakly prime, because it can be changed into another prime (1311242365403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655621182704 + 655621182705.

It is an arithmetic number, because the mean of its divisors is an integer number (655621182705).

Almost surely, 21311242365409 is an apocalyptic number.

It is an amenable number.

1311242365409 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311242365409 is an equidigital number, since it uses as much as digits as its factorization.

1311242365409 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 155520, while the sum is 41.

The spelling of 1311242365409 in words is "one trillion, three hundred eleven billion, two hundred forty-two million, three hundred sixty-five thousand, four hundred nine".