13112432424000 has 1344 divisors, whose sum is σ = 58174161357312. Its totient is φ = 2745280512000.

The previous prime is 13112432423999. The next prime is 13112432424019. The reversal of 13112432424000 is 42423421131.

13112432424000 is a `hidden beast` number, since 1 + 3 + 1 + 12 + 4 + 3 + 242 + 400 + 0 = 666.

13112432424000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (1344).

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 858304362 + ... + 858319638.

It is an arithmetic number, because the mean of its divisors is an integer number (43284346248).

Almost surely, 2^{13112432424000} is an apocalyptic number.

13112432424000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13112432424000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (29087080678656).

13112432424000 is an abundant number, since it is smaller than the sum of its proper divisors (45061728933312).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13112432424000 is a wasteful number, since it uses less digits than its factorization.

13112432424000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15461 (or 15438 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 13112432424000 its reverse (42423421131), we get a palindrome (13154855845131).

The spelling of 13112432424000 in words is "thirteen trillion, one hundred twelve billion, four hundred thirty-two million, four hundred twenty-four thousand".