Base | Representation |
---|---|
bin | 10011000101001100001… |
… | …111110100110101000111 |
3 | 11122100112212101010211201 |
4 | 103011030033310311013 |
5 | 132440412011222442 |
6 | 2442213254443331 |
7 | 163506566105632 |
oct | 23051417646507 |
9 | 4570485333751 |
10 | 1311244242247 |
11 | 466106210885 |
12 | 192165063547 |
13 | 9685a7c9814 |
14 | 47670a76c19 |
15 | 2419615c7b7 |
hex | 1314c3f4d47 |
1311244242247 has 2 divisors, whose sum is σ = 1311244242248. Its totient is φ = 1311244242246.
The previous prime is 1311244242241. The next prime is 1311244242289. The reversal of 1311244242247 is 7422424421131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311244242247 - 215 = 1311244209479 is a prime.
It is a super-2 number, since 2×13112442422472 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311244242241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655622121123 + 655622121124.
It is an arithmetic number, because the mean of its divisors is an integer number (655622121124).
Almost surely, 21311244242247 is an apocalyptic number.
1311244242247 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311244242247 is an equidigital number, since it uses as much as digits as its factorization.
1311244242247 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 86016, while the sum is 37.
Adding to 1311244242247 its reverse (7422424421131), we get a palindrome (8733668663378).
The spelling of 1311244242247 in words is "one trillion, three hundred eleven billion, two hundred forty-four million, two hundred forty-two thousand, two hundred forty-seven".
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