Search a number
-
+
13112510051410 = 25711231519375233
BaseRepresentation
bin1011111011001111111010…
…0000001111010001010010
31201102112200101000022212121
42332303332200033101102
53204313410033121120
643515445353244454
72522230136303110
oct276637640172122
951375611008777
1013112510051410
1141a5a91099660
12157936110372a
137416731c3833
14334912714ab0
1517b146ce35aa
hexbecfe80f452

13112510051410 has 256 divisors, whose sum is σ = 30948180738048. Its totient is φ = 3878544384000.

The previous prime is 13112510051327. The next prime is 13112510051413. The reversal of 13112510051410 is 1415001521131.

It is not an unprimeable number, because it can be changed into a prime (13112510051413) by changing a digit.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 2505732154 + ... + 2505737386.

It is an arithmetic number, because the mean of its divisors is an integer number (120891331008).

Almost surely, 213112510051410 is an apocalyptic number.

13112510051410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13112510051410 is an abundant number, since it is smaller than the sum of its proper divisors (17835670686638).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13112510051410 is a wasteful number, since it uses less digits than its factorization.

13112510051410 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6369.

The product of its (nonzero) digits is 600, while the sum is 25.

Adding to 13112510051410 its reverse (1415001521131), we get a palindrome (14527511572541).

The spelling of 13112510051410 in words is "thirteen trillion, one hundred twelve billion, five hundred ten million, fifty-one thousand, four hundred ten".