Base | Representation |
---|---|
bin | 1011111011001111111010… |
… | …0000001111010001010101 |
3 | 1201102112200101000022212201 |
4 | 2332303332200033101111 |
5 | 3204313410033121123 |
6 | 43515445353244501 |
7 | 2522230136303113 |
oct | 276637640172125 |
9 | 51375611008781 |
10 | 13112510051413 |
11 | 41a5a91099663 |
12 | 1579361103731 |
13 | 7416731c3836 |
14 | 334912714ab3 |
15 | 17b146ce35ad |
hex | becfe80f455 |
13112510051413 has 2 divisors, whose sum is σ = 13112510051414. Its totient is φ = 13112510051412.
The previous prime is 13112510051327. The next prime is 13112510051447. The reversal of 13112510051413 is 31415001521131.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11875970499409 + 1236539552004 = 3446153^2 + 1111998^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13112510051413 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13112510051453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556255025706 + 6556255025707.
It is an arithmetic number, because the mean of its divisors is an integer number (6556255025707).
Almost surely, 213112510051413 is an apocalyptic number.
It is an amenable number.
13112510051413 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112510051413 is an equidigital number, since it uses as much as digits as its factorization.
13112510051413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1800, while the sum is 28.
Adding to 13112510051413 its reverse (31415001521131), we get a palindrome (44527511572544).
The spelling of 13112510051413 in words is "thirteen trillion, one hundred twelve billion, five hundred ten million, fifty-one thousand, four hundred thirteen".
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