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13112513253361 is a prime number
BaseRepresentation
bin1011111011001111111010…
…1100011100111111110001
31201102112200121001000010101
42332303332230130333301
53204313411343101421
643515445550032401
72522230205440204
oct276637654347761
951375617030111
1013112513253361
1141a5a929862a5
1215793621a8701
13741673a75092
14334912d0993b
1517b147227191
hexbecfeb1cff1

13112513253361 has 2 divisors, whose sum is σ = 13112513253362. Its totient is φ = 13112513253360.

The previous prime is 13112513253353. The next prime is 13112513253379. The reversal of 13112513253361 is 16335231521131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11518149945600 + 1594363307761 = 3393840^2 + 1262681^2 .

It is a cyclic number.

It is not a de Polignac number, because 13112513253361 - 23 = 13112513253353 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13112513253361.

It is not a weakly prime, because it can be changed into another prime (13112513253061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556256626680 + 6556256626681.

It is an arithmetic number, because the mean of its divisors is an integer number (6556256626681).

Almost surely, 213112513253361 is an apocalyptic number.

It is an amenable number.

13112513253361 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112513253361 is an equidigital number, since it uses as much as digits as its factorization.

13112513253361 is an evil number, because the sum of its binary digits is even.

The product of its digits is 48600, while the sum is 37.

Adding to 13112513253361 its reverse (16335231521131), we get a palindrome (29447744774492).

The spelling of 13112513253361 in words is "thirteen trillion, one hundred twelve billion, five hundred thirteen million, two hundred fifty-three thousand, three hundred sixty-one".