Base | Representation |
---|---|
bin | 1011111011001111111010… |
… | …1100011100111111101001 |
3 | 1201102112200121001000010002 |
4 | 2332303332230130333221 |
5 | 3204313411343101403 |
6 | 43515445550032345 |
7 | 2522230205440163 |
oct | 276637654347751 |
9 | 51375617030102 |
10 | 13112513253353 |
11 | 41a5a92986298 |
12 | 15793621a86b5 |
13 | 741673a75087 |
14 | 334912d09933 |
15 | 17b147227188 |
hex | becfeb1cfe9 |
13112513253353 has 2 divisors, whose sum is σ = 13112513253354. Its totient is φ = 13112513253352.
The previous prime is 13112513253317. The next prime is 13112513253361. The reversal of 13112513253353 is 35335231521131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11736708588544 + 1375804664809 = 3425888^2 + 1172947^2 .
It is a cyclic number.
It is not a de Polignac number, because 13112513253353 - 212 = 13112513249257 is a prime.
It is not a weakly prime, because it can be changed into another prime (13112513253313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556256626676 + 6556256626677.
It is an arithmetic number, because the mean of its divisors is an integer number (6556256626677).
Almost surely, 213112513253353 is an apocalyptic number.
It is an amenable number.
13112513253353 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112513253353 is an equidigital number, since it uses as much as digits as its factorization.
13112513253353 is an evil number, because the sum of its binary digits is even.
The product of its digits is 121500, while the sum is 38.
Adding to 13112513253353 its reverse (35335231521131), we get a palindrome (48447744774484).
The spelling of 13112513253353 in words is "thirteen trillion, one hundred twelve billion, five hundred thirteen million, two hundred fifty-three thousand, three hundred fifty-three".
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