Base | Representation |
---|---|
bin | 1011111011001111111011… |
… | …1110011000101000110101 |
3 | 1201102112200220212211022212 |
4 | 2332303332332120220311 |
5 | 3204313414044012401 |
6 | 43515450234503205 |
7 | 2522230263416036 |
oct | 276637676305065 |
9 | 51375626784285 |
10 | 13112517954101 |
11 | 41a5a955a7005 |
12 | 1579363894b05 |
13 | 741674a2c897 |
14 | 3349137b0a8d |
15 | 17b147854dbb |
hex | becfef98a35 |
13112517954101 has 2 divisors, whose sum is σ = 13112517954102. Its totient is φ = 13112517954100.
The previous prime is 13112517954083. The next prime is 13112517954131. The reversal of 13112517954101 is 10145971521131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10090952743876 + 3021565210225 = 3176626^2 + 1738265^2 .
It is a cyclic number.
It is not a de Polignac number, because 13112517954101 - 222 = 13112513759797 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13112517954131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556258977050 + 6556258977051.
It is an arithmetic number, because the mean of its divisors is an integer number (6556258977051).
Almost surely, 213112517954101 is an apocalyptic number.
It is an amenable number.
13112517954101 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112517954101 is an equidigital number, since it uses as much as digits as its factorization.
13112517954101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 37800, while the sum is 41.
The spelling of 13112517954101 in words is "thirteen trillion, one hundred twelve billion, five hundred seventeen million, nine hundred fifty-four thousand, one hundred one".
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