Base | Representation |
---|---|
bin | 1011111011001111111100… |
… | …0110011000101010011001 |
3 | 1201102112201001211101012212 |
4 | 2332303333012120222121 |
5 | 3204313420113120403 |
6 | 43515450351444505 |
7 | 2522230320302342 |
oct | 276637706305231 |
9 | 51375631741185 |
10 | 13112520051353 |
11 | 41a5a967a9778 |
12 | 1579364526735 |
13 | 7416752b5368 |
14 | 334913b990c9 |
15 | 17b147b1b4d8 |
hex | becff198a99 |
13112520051353 has 2 divisors, whose sum is σ = 13112520051354. Its totient is φ = 13112520051352.
The previous prime is 13112520051329. The next prime is 13112520051361. The reversal of 13112520051353 is 35315002521131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12167518310809 + 945001740544 = 3488197^2 + 972112^2 .
It is an emirp because it is prime and its reverse (35315002521131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13112520051353 - 232 = 13108225084057 is a prime.
It is not a weakly prime, because it can be changed into another prime (13112520051313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556260025676 + 6556260025677.
It is an arithmetic number, because the mean of its divisors is an integer number (6556260025677).
Almost surely, 213112520051353 is an apocalyptic number.
It is an amenable number.
13112520051353 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112520051353 is an equidigital number, since it uses as much as digits as its factorization.
13112520051353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13500, while the sum is 32.
Adding to 13112520051353 its reverse (35315002521131), we get a palindrome (48427522572484).
The spelling of 13112520051353 in words is "thirteen trillion, one hundred twelve billion, five hundred twenty million, fifty-one thousand, three hundred fifty-three".
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