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13112555103 = 332381203969
BaseRepresentation
bin11000011011001000…
…11011011001011111
31020211211120211001000
430031210123121133
5203323303230403
610005051321343
7642640610424
oct141544333137
936754524030
1013112555103
1156197717aa
12265b450253
13130c7c005b
148c56a7d4b
1551b2867a3
hex30d91b65f

13112555103 has 16 divisors (see below), whose sum is σ = 19434261600. Its totient is φ = 8737989120.

The previous prime is 13112555089. The next prime is 13112555173. The reversal of 13112555103 is 30155521131.

13112555103 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 2 + 555 + 103 = 666.

It is not a de Polignac number, because 13112555103 - 24 = 13112555087 is a prime.

It is a super-2 number, since 2×131125551032 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13112555173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 37698 + ... + 166271.

It is an arithmetic number, because the mean of its divisors is an integer number (1214641350).

Almost surely, 213112555103 is an apocalyptic number.

13112555103 is a deficient number, since it is larger than the sum of its proper divisors (6321706497).

13112555103 is a wasteful number, since it uses less digits than its factorization.

13112555103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 206359 (or 206353 counting only the distinct ones).

The product of its (nonzero) digits is 2250, while the sum is 27.

The spelling of 13112555103 in words is "thirteen billion, one hundred twelve million, five hundred fifty-five thousand, one hundred three".

Divisors: 1 3 9 27 2381 7143 21429 64287 203969 611907 1835721 5507163 485650189 1456950567 4370851701 13112555103