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13112555173 is a prime number
BaseRepresentation
bin11000011011001000…
…11011011010100101
31020211211120211010121
430031210123122211
5203323303231143
610005051321541
7642640610554
oct141544333245
936754524117
1013112555173
115619771863
12265b4502b1
13130c7c00b3
148c56a7d9b
1551b2867ed
hex30d91b6a5

13112555173 has 2 divisors, whose sum is σ = 13112555174. Its totient is φ = 13112555172.

The previous prime is 13112555089. The next prime is 13112555189. The reversal of 13112555173 is 37155521131.

13112555173 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11017021444 + 2095533729 = 104962^2 + 45777^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13112555173 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13112555273) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556277586 + 6556277587.

It is an arithmetic number, because the mean of its divisors is an integer number (6556277587).

Almost surely, 213112555173 is an apocalyptic number.

It is an amenable number.

13112555173 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112555173 is an equidigital number, since it uses as much as digits as its factorization.

13112555173 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 15750, while the sum is 34.

The spelling of 13112555173 in words is "thirteen billion, one hundred twelve million, five hundred fifty-five thousand, one hundred seventy-three".