Base | Representation |
---|---|
bin | 11000011011001000… |
… | …11011011001010001 |
3 | 1020211211120211000111 |
4 | 30031210123121101 |
5 | 203323303230324 |
6 | 10005051321321 |
7 | 642640610404 |
oct | 141544333121 |
9 | 36754524014 |
10 | 13112555089 |
11 | 5619771797 |
12 | 265b450241 |
13 | 130c7c004a |
14 | 8c56a7d3b |
15 | 51b286794 |
hex | 30d91b651 |
13112555089 has 2 divisors, whose sum is σ = 13112555090. Its totient is φ = 13112555088.
The previous prime is 13112555087. The next prime is 13112555173. The reversal of 13112555089 is 98055521131.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9390579025 + 3721976064 = 96905^2 + 61008^2 .
It is a cyclic number.
It is not a de Polignac number, because 13112555089 - 21 = 13112555087 is a prime.
Together with 13112555087, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13112555087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556277544 + 6556277545.
It is an arithmetic number, because the mean of its divisors is an integer number (6556277545).
Almost surely, 213112555089 is an apocalyptic number.
It is an amenable number.
13112555089 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112555089 is an equidigital number, since it uses as much as digits as its factorization.
13112555089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 40.
The spelling of 13112555089 in words is "thirteen billion, one hundred twelve million, five hundred fifty-five thousand, eighty-nine".
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