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1311255523 is a prime number
BaseRepresentation
bin100111000101000…
…0010101111100011
310101101100200102101
41032022002233203
510141140134043
6334040431231
744331326254
oct11612025743
93341320371
101311255523
11613195756
12307178517
1317b879156
14c6210b2b
157a1b524d
hex4e282be3

1311255523 has 2 divisors, whose sum is σ = 1311255524. Its totient is φ = 1311255522.

The previous prime is 1311255521. The next prime is 1311255541. The reversal of 1311255523 is 3255521131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1311255523 - 21 = 1311255521 is a prime.

Together with 1311255521, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1311255491 and 1311255500.

It is not a weakly prime, because it can be changed into another prime (1311255521) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655627761 + 655627762.

It is an arithmetic number, because the mean of its divisors is an integer number (655627762).

Almost surely, 21311255523 is an apocalyptic number.

1311255523 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311255523 is an equidigital number, since it uses as much as digits as its factorization.

1311255523 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4500, while the sum is 28.

The square root of 1311255523 is about 36211.2623778846. The cubic root of 1311255523 is about 1094.5336304114.

Adding to 1311255523 its reverse (3255521131), we get a palindrome (4566776654).

It can be divided in two parts, 13112 and 55523, that added together give a triangular number (68635 = T370).

The spelling of 1311255523 in words is "one billion, three hundred eleven million, two hundred fifty-five thousand, five hundred twenty-three".