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1311260655469 is a prime number
BaseRepresentation
bin10011000101001101001…
…110011011111101101101
311122100121000021000112211
4103011031032123331231
5132440430211433334
62442215042330421
7163510155445612
oct23051516337555
94570530230484
101311260655469
11466114501326
1219216a659a11
139686102549b
1447672d0a509
1524197800a64
hex1314d39bf6d

1311260655469 has 2 divisors, whose sum is σ = 1311260655470. Its totient is φ = 1311260655468.

The previous prime is 1311260655437. The next prime is 1311260655491. The reversal of 1311260655469 is 9645560621131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 942720599844 + 368540055625 = 970938^2 + 607075^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311260655469 - 25 = 1311260655437 is a prime.

It is a super-2 number, since 2×13112606554692 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311260695469) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655630327734 + 655630327735.

It is an arithmetic number, because the mean of its divisors is an integer number (655630327735).

Almost surely, 21311260655469 is an apocalyptic number.

It is an amenable number.

1311260655469 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311260655469 is an equidigital number, since it uses as much as digits as its factorization.

1311260655469 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1166400, while the sum is 49.

The spelling of 1311260655469 in words is "one trillion, three hundred eleven billion, two hundred sixty million, six hundred fifty-five thousand, four hundred sixty-nine".