Base | Representation |
---|---|
bin | 1011111011010001101110… |
… | …1101010010000111100011 |
3 | 1201102120221111221210222212 |
4 | 2332310123231102013203 |
5 | 3204320411000311321 |
6 | 43520010134552335 |
7 | 2522245236006323 |
oct | 276643355220743 |
9 | 51376844853885 |
10 | 13113000010211 |
11 | 41a6212717992 |
12 | 15794792086ab |
13 | 74172087139a |
14 | 33495b815283 |
15 | 17b174d2655b |
hex | bed1bb521e3 |
13113000010211 has 2 divisors, whose sum is σ = 13113000010212. Its totient is φ = 13113000010210.
The previous prime is 13113000010193. The next prime is 13113000010217. The reversal of 13113000010211 is 11201000031131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13113000010211 - 242 = 8714953499107 is a prime.
It is a super-2 number, since 2×131130000102112 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13113000010217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556500005105 + 6556500005106.
It is an arithmetic number, because the mean of its divisors is an integer number (6556500005106).
Almost surely, 213113000010211 is an apocalyptic number.
13113000010211 is a deficient number, since it is larger than the sum of its proper divisors (1).
13113000010211 is an equidigital number, since it uses as much as digits as its factorization.
13113000010211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 13113000010211 its reverse (11201000031131), we get a palindrome (24314000041342).
The spelling of 13113000010211 in words is "thirteen trillion, one hundred thirteen billion, ten thousand, two hundred eleven".
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