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1311300223657 is a prime number
BaseRepresentation
bin10011000101001111100…
…101011000001010101001
311122100200202201021220021
4103011033211120022221
5132441020324124112
62442223014400441
7163511145665014
oct23051745301251
94570622637807
101311300223657
11466134877506
1219217b960121
139686929a608
144767828a37b
152419b019907
hex1314f9582a9

1311300223657 has 2 divisors, whose sum is σ = 1311300223658. Its totient is φ = 1311300223656.

The previous prime is 1311300223613. The next prime is 1311300223703. The reversal of 1311300223657 is 7563220031131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1308909893776 + 2390329881 = 1144076^2 + 48891^2 .

It is an emirp because it is prime and its reverse (7563220031131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311300223657 - 27 = 1311300223529 is a prime.

It is not a weakly prime, because it can be changed into another prime (1311300203657) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655650111828 + 655650111829.

It is an arithmetic number, because the mean of its divisors is an integer number (655650111829).

Almost surely, 21311300223657 is an apocalyptic number.

It is an amenable number.

1311300223657 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311300223657 is an equidigital number, since it uses as much as digits as its factorization.

1311300223657 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 22680, while the sum is 34.

Adding to 1311300223657 its reverse (7563220031131), we get a palindrome (8874520254788).

The spelling of 1311300223657 in words is "one trillion, three hundred eleven billion, three hundred million, two hundred twenty-three thousand, six hundred fifty-seven".