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1311300234397 is a prime number
BaseRepresentation
bin10011000101001111100…
…101011010110010011101
311122100200202201211122001
4103011033211122302131
5132441020330000042
62442223014522301
7163511146041226
oct23051745326235
94570622654561
101311300234397
1146613488458a
1219217b966391
13968692a247a
144767829024d
152419b01cbb7
hex1314f95ac9d

1311300234397 has 2 divisors, whose sum is σ = 1311300234398. Its totient is φ = 1311300234396.

The previous prime is 1311300234383. The next prime is 1311300234403. The reversal of 1311300234397 is 7934320031131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1224992958436 + 86307275961 = 1106794^2 + 293781^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311300234397 - 27 = 1311300234269 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311300234697) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655650117198 + 655650117199.

It is an arithmetic number, because the mean of its divisors is an integer number (655650117199).

Almost surely, 21311300234397 is an apocalyptic number.

It is an amenable number.

1311300234397 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311300234397 is an equidigital number, since it uses as much as digits as its factorization.

1311300234397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40824, while the sum is 37.

The spelling of 1311300234397 in words is "one trillion, three hundred eleven billion, three hundred million, two hundred thirty-four thousand, three hundred ninety-seven".