1311300234640 has 640 divisors, whose sum is σ = 3758969410560. Its totient is φ = 419561472000.

The previous prime is 1311300234611. The next prime is 1311300234653. The reversal of 1311300234640 is 464320031131.

It is a junction number, because it is equal to n+sod(n) for n = 1311300234599 and 1311300234608.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 3370951566 + ... + 3370951954.

It is an arithmetic number, because the mean of its divisors is an integer number (5873389704).

Almost surely, 2^{1311300234640} is an apocalyptic number.

1311300234640 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1311300234640, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1879484705280).

1311300234640 is an abundant number, since it is smaller than the sum of its proper divisors (2447669175920).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311300234640 is a wasteful number, since it uses less digits than its factorization.

1311300234640 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 651 (or 645 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1311300234640 its reverse (464320031131), we get a palindrome (1775620265771).

The spelling of 1311300234640 in words is "one trillion, three hundred eleven billion, three hundred million, two hundred thirty-four thousand, six hundred forty".