Base | Representation |
---|---|
bin | 10011000101001111100… |
… | …101011010110110011101 |
3 | 11122100200202201211222112 |
4 | 103011033211122312131 |
5 | 132441020330002103 |
6 | 2442223014523405 |
7 | 163511146042043 |
oct | 23051745326635 |
9 | 4570622654875 |
10 | 1311300234653 |
11 | 4661348847a2 |
12 | 19217b966565 |
13 | 968692a2616 |
14 | 47678290393 |
15 | 2419b01ccd8 |
hex | 1314f95ad9d |
1311300234653 has 2 divisors, whose sum is σ = 1311300234654. Its totient is φ = 1311300234652.
The previous prime is 1311300234611. The next prime is 1311300234661. The reversal of 1311300234653 is 3564320031131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1204631368249 + 106668866404 = 1097557^2 + 326602^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311300234653 - 28 = 1311300234397 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311300231653) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655650117326 + 655650117327.
It is an arithmetic number, because the mean of its divisors is an integer number (655650117327).
Almost surely, 21311300234653 is an apocalyptic number.
It is an amenable number.
1311300234653 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311300234653 is an equidigital number, since it uses as much as digits as its factorization.
1311300234653 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19440, while the sum is 32.
Adding to 1311300234653 its reverse (3564320031131), we get a palindrome (4875620265784).
The spelling of 1311300234653 in words is "one trillion, three hundred eleven billion, three hundred million, two hundred thirty-four thousand, six hundred fifty-three".
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