Base | Representation |
---|---|
bin | 10011000101001111100… |
… | …101101101100100001101 |
3 | 11122100200202212202010122 |
4 | 103011033211231210031 |
5 | 132441020334430214 |
6 | 2442223020314325 |
7 | 163511146511402 |
oct | 23051745554415 |
9 | 4570622782118 |
10 | 1311300311309 |
11 | 46613492734a |
12 | 19217b9a29a5 |
13 | 968692cb491 |
14 | 476782b02a9 |
15 | 2419b03588e |
hex | 1314f96d90d |
1311300311309 has 2 divisors, whose sum is σ = 1311300311310. Its totient is φ = 1311300311308.
The previous prime is 1311300311213. The next prime is 1311300311323. The reversal of 1311300311309 is 9031130031131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1129267528900 + 182032782409 = 1062670^2 + 426653^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1311300311309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311300311329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655650155654 + 655650155655.
It is an arithmetic number, because the mean of its divisors is an integer number (655650155655).
Almost surely, 21311300311309 is an apocalyptic number.
It is an amenable number.
1311300311309 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311300311309 is an equidigital number, since it uses as much as digits as its factorization.
1311300311309 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 729, while the sum is 26.
The spelling of 1311300311309 in words is "one trillion, three hundred eleven billion, three hundred million, three hundred eleven thousand, three hundred nine".
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