13113004013 has 2 divisors, whose sum is σ = 13113004014. Its totient is φ = 13113004012.

The previous prime is 13113003929. The next prime is 13113004027. The reversal of 13113004013 is 31040031131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10916488324 + 2196515689 = 104482^2 + 46867^2 .

It is a cyclic number.

It is not a de Polignac number, because 13113004013 - 2²⁴ = 13096226797 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13113003982 and 13113004000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13113004813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556502006 + 6556502007.

It is an arithmetic number, because the mean of its divisors is an integer number (6556502007).

Almost surely, 2^13113004013 is an apocalyptic number.

It is an amenable number.

13113004013 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113004013 is an equidigital number, since it uses as much as digits as its factorization.

13113004013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 13113004013 its reverse (31040031131), we get a palindrome (44153035144).

The spelling of 13113004013 in words is "thirteen billion, one hundred thirteen million, four thousand, thirteen".