Base | Representation |
---|---|
bin | 111101000011111110… |
… | …1101011010101101101 |
3 | 110112110200102211221102 |
4 | 1322013331223111231 |
5 | 4122023302030331 |
6 | 140123525212445 |
7 | 12321345361415 |
oct | 1720775532555 |
9 | 415420384842 |
10 | 131130111341 |
11 | 50680590549 |
12 | 214b7261125 |
13 | c49a069078 |
14 | 64bd605645 |
15 | 36271964cb |
hex | 1e87f6b56d |
131130111341 has 2 divisors, whose sum is σ = 131130111342. Its totient is φ = 131130111340.
The previous prime is 131130111311. The next prime is 131130111353. The reversal of 131130111341 is 143111031131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 66793818025 + 64336293316 = 258445^2 + 253646^2 .
It is a cyclic number.
It is not a de Polignac number, because 131130111341 - 222 = 131125917037 is a prime.
It is a super-2 number, since 2×1311301113412 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131130111311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65565055670 + 65565055671.
It is an arithmetic number, because the mean of its divisors is an integer number (65565055671).
Almost surely, 2131130111341 is an apocalyptic number.
It is an amenable number.
131130111341 is a deficient number, since it is larger than the sum of its proper divisors (1).
131130111341 is an equidigital number, since it uses as much as digits as its factorization.
131130111341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 131130111341 its reverse (143111031131), we get a palindrome (274241142472).
The spelling of 131130111341 in words is "one hundred thirty-one billion, one hundred thirty million, one hundred eleven thousand, three hundred forty-one".
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