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13113013219973 is a prime number
BaseRepresentation
bin1011111011010001110001…
…1111101011001010000101
31201102120222102210221101022
42332310130133223022011
53204320422341014343
643520011330040525
72522245456204622
oct276643437531205
951376872727338
1013113013219973
1141a621a11a647
121579481719145
13741723517c04
1433495d493349
1517b176085568
hexbed1c7eb285

13113013219973 has 2 divisors, whose sum is σ = 13113013219974. Its totient is φ = 13113013219972.

The previous prime is 13113013219963. The next prime is 13113013219979. The reversal of 13113013219973 is 37991231031131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11232431596324 + 1880581623649 = 3351482^2 + 1371343^2 .

It is a cyclic number.

It is not a de Polignac number, because 13113013219973 - 26 = 13113013219909 is a prime.

It is a super-2 number, since 2×131130132199732 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13113013219979) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556506609986 + 6556506609987.

It is an arithmetic number, because the mean of its divisors is an integer number (6556506609987).

Almost surely, 213113013219973 is an apocalyptic number.

It is an amenable number.

13113013219973 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113013219973 is an equidigital number, since it uses as much as digits as its factorization.

13113013219973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 91854, while the sum is 44.

The spelling of 13113013219973 in words is "thirteen trillion, one hundred thirteen billion, thirteen million, two hundred nineteen thousand, nine hundred seventy-three".