1311302411 has 2 divisors, whose sum is σ = 1311302412. Its totient is φ = 1311302410.

The previous prime is 1311302401. The next prime is 1311302413. The reversal of 1311302411 is 1142031131.

It is a strong prime.

It is an emirp because it is prime and its reverse (1142031131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311302411 - 2¹⁸ = 1311040267 is a prime.

Together with 1311302413, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1311302411.

It is not a weakly prime, because it can be changed into another prime (1311302413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655651205 + 655651206.

It is an arithmetic number, because the mean of its divisors is an integer number (655651206).

Almost surely, 2^1311302411 is an apocalyptic number.

1311302411 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311302411 is an equidigital number, since it uses as much as digits as its factorization.

1311302411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 1311302411 is about 36211.9097949832. The cubic root of 1311302411 is about 1094.5466764018.

Adding to 1311302411 its reverse (1142031131), we get a palindrome (2453333542).

The spelling of 1311302411 in words is "one billion, three hundred eleven million, three hundred two thousand, four hundred eleven".