13113041232 has 40 divisors (see below), whose sum is σ = 33887179296. Its totient is φ = 4369488256.

The previous prime is 13113041167. The next prime is 13113041233. The reversal of 13113041232 is 23214031131.

It is a junction number, because it is equal to n+sod(n) for n = 13113041199 and 13113041208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13113041233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 95743 + ... + 188129.

Almost surely, 2^13113041232 is an apocalyptic number.

13113041232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13113041232 is an abundant number, since it is smaller than the sum of its proper divisors (20774138064).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13113041232 is a wasteful number, since it uses less digits than its factorization.

13113041232 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 95355 (or 95349 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 13113041232 its reverse (23214031131), we get a palindrome (36327072363).

The spelling of 13113041232 in words is "thirteen billion, one hundred thirteen million, forty-one thousand, two hundred thirty-two".