Search a number
-
+
13113058690477 is a prime number
BaseRepresentation
bin1011111011010001111100…
…1101001000010110101101
31201102121002121101002012001
42332310133031020112231
53204321021011043402
643520020032412301
72522246550535654
oct276643715102655
951377077332161
1013113058690477
1141a6242857279
1215794949a7091
1374172ca78735
1433496552c19b
1517b17a068187
hexbed1f3485ad

13113058690477 has 2 divisors, whose sum is σ = 13113058690478. Its totient is φ = 13113058690476.

The previous prime is 13113058690463. The next prime is 13113058690483. The reversal of 13113058690477 is 77409685031131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12659605945156 + 453452745321 = 3558034^2 + 673389^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13113058690477 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13113058690427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556529345238 + 6556529345239.

It is an arithmetic number, because the mean of its divisors is an integer number (6556529345239).

Almost surely, 213113058690477 is an apocalyptic number.

It is an amenable number.

13113058690477 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113058690477 is an equidigital number, since it uses as much as digits as its factorization.

13113058690477 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3810240, while the sum is 55.

The spelling of 13113058690477 in words is "thirteen trillion, one hundred thirteen billion, fifty-eight million, six hundred ninety thousand, four hundred seventy-seven".