13113101101 has 2 divisors, whose sum is σ = 13113101102. Its totient is φ = 13113101100.

The previous prime is 13113101093. The next prime is 13113101119. The reversal of 13113101101 is 10110131131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13112540100 + 561001 = 114510^2 + 749^2 .

It is a cyclic number.

It is not a de Polignac number, because 13113101101 - 2³ = 13113101093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13113101201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556550550 + 6556550551.

It is an arithmetic number, because the mean of its divisors is an integer number (6556550551).

Almost surely, 2^13113101101 is an apocalyptic number.

It is an amenable number.

13113101101 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113101101 is an equidigital number, since it uses as much as digits as its factorization.

13113101101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 13113101101 its reverse (10110131131), we get a palindrome (23223232232).

The spelling of 13113101101 in words is "thirteen billion, one hundred thirteen million, one hundred one thousand, one hundred one".