Base | Representation |
---|---|
bin | 111101000100000000… |
… | …1000111010011001100 |
3 | 110112110202010121211021 |
4 | 1322020001013103030 |
5 | 4122024014343200 |
6 | 140124000403524 |
7 | 12321356133211 |
oct | 1721001072314 |
9 | 415422117737 |
10 | 131131012300 |
11 | 50681046442 |
12 | 214b76165a4 |
13 | c49a2c3192 |
14 | 64bd79bb08 |
15 | 36272c341a |
hex | 1e880474cc |
131131012300 has 36 divisors (see below), whose sum is σ = 286438795216. Its totient is φ = 52105032000.
The previous prime is 131131012283. The next prime is 131131012387. The reversal of 131131012300 is 3210131131.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4326987 + ... + 4357186.
Almost surely, 2131131012300 is an apocalyptic number.
131131012300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131131012300 is an abundant number, since it is smaller than the sum of its proper divisors (155307782916).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131131012300 is a wasteful number, since it uses less digits than its factorization.
131131012300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8684338 (or 8684331 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 131131012300 its reverse (3210131131), we get a palindrome (134341143431).
The spelling of 131131012300 in words is "one hundred thirty-one billion, one hundred thirty-one million, twelve thousand, three hundred".
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