Base | Representation |
---|---|
bin | 10011000101010000001… |
… | …011111001010111001111 |
3 | 11122100201110201021222202 |
4 | 103011100023321113033 |
5 | 132441030420233403 |
6 | 2442224015032115 |
7 | 163511330551436 |
oct | 23052013712717 |
9 | 4570643637882 |
10 | 1311310321103 |
11 | 46613a543902 |
12 | 19218320b63b |
13 | 9686b3c4633 |
14 | 4767975811d |
15 | 2419bd61688 |
hex | 131502f95cf |
1311310321103 has 2 divisors, whose sum is σ = 1311310321104. Its totient is φ = 1311310321102.
The previous prime is 1311310321003. The next prime is 1311310321141. The reversal of 1311310321103 is 3011230131131.
It is a strong prime.
It is an emirp because it is prime and its reverse (3011230131131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1311310321103 - 28 = 1311310320847 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311310321003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655655160551 + 655655160552.
It is an arithmetic number, because the mean of its divisors is an integer number (655655160552).
Almost surely, 21311310321103 is an apocalyptic number.
1311310321103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311310321103 is an equidigital number, since it uses as much as digits as its factorization.
1311310321103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 1311310321103 its reverse (3011230131131), we get a palindrome (4322540452234).
The spelling of 1311310321103 in words is "one trillion, three hundred eleven billion, three hundred ten million, three hundred twenty-one thousand, one hundred three".
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