131131110323 has 2 divisors, whose sum is σ = 131131110324. Its totient is φ = 131131110322.

The previous prime is 131131110307. The next prime is 131131110343. The reversal of 131131110323 is 323011131131.

It is an a-pointer prime, because the next prime (131131110343) can be obtained adding 131131110323 to its sum of digits (20).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131131110323 - 2⁴ = 131131110307 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131131110295 and 131131110304.

It is not a weakly prime, because it can be changed into another prime (131131110343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65565555161 + 65565555162.

It is an arithmetic number, because the mean of its divisors is an integer number (65565555162).

Almost surely, 2^131131110323 is an apocalyptic number.

131131110323 is a deficient number, since it is larger than the sum of its proper divisors (1).

131131110323 is an equidigital number, since it uses as much as digits as its factorization.

131131110323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 131131110323 its reverse (323011131131), we get a palindrome (454142241454).

The spelling of 131131110323 in words is "one hundred thirty-one billion, one hundred thirty-one million, one hundred ten thousand, three hundred twenty-three".