Base | Representation |
---|---|
bin | 11000011011001101… |
… | …00011011010010011 |
3 | 1020211212122010020122 |
4 | 30031212203122103 |
5 | 203323424042321 |
6 | 10005111300455 |
7 | 642645420563 |
oct | 141546433223 |
9 | 36755563218 |
10 | 13113112211 |
11 | 561a012321 |
12 | 265b67a72b |
13 | 130c9567c4 |
14 | 8c57b0da3 |
15 | 51b3468ab |
hex | 30d9a3693 |
13113112211 has 2 divisors, whose sum is σ = 13113112212. Its totient is φ = 13113112210.
The previous prime is 13113112147. The next prime is 13113112213. The reversal of 13113112211 is 11221131131.
13113112211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13113112211 - 26 = 13113112147 is a prime.
Together with 13113112213, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13113112211.
It is not a weakly prime, because it can be changed into another prime (13113112213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556556105 + 6556556106.
It is an arithmetic number, because the mean of its divisors is an integer number (6556556106).
Almost surely, 213113112211 is an apocalyptic number.
13113112211 is a deficient number, since it is larger than the sum of its proper divisors (1).
13113112211 is an equidigital number, since it uses as much as digits as its factorization.
13113112211 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 36, while the sum is 17.
Adding to 13113112211 its reverse (11221131131), we get a palindrome (24334243342).
The spelling of 13113112211 in words is "thirteen billion, one hundred thirteen million, one hundred twelve thousand, two hundred eleven".
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