13113123304240 has 40 divisors (see below), whose sum is σ = 30488195818080. Its totient is φ = 5245217642496.

The previous prime is 13113123304201. The next prime is 13113123304249. The reversal of 13113123304240 is 4240332131131.

13113123304240 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (40).

It is a junction number, because it is equal to n+sod(n) for n = 13113123304199 and 13113123304208.

It is not an unprimeable number, because it can be changed into a prime (13113123304249) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16426837 + ... + 17206603.

It is an arithmetic number, because the mean of its divisors is an integer number (762204895452).

Almost surely, 2^{13113123304240} is an apocalyptic number.

13113123304240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13113123304240 is an abundant number, since it is smaller than the sum of its proper divisors (17375072513840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13113123304240 is a wasteful number, since it uses less digits than its factorization.

13113123304240 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 989989 (or 989983 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 13113123304240 its reverse (4240332131131), we get a palindrome (17353455435371).

The spelling of 13113123304240 in words is "thirteen trillion, one hundred thirteen billion, one hundred twenty-three million, three hundred four thousand, two hundred forty".