131131244341404 has 18 divisors (see below), whose sum is σ = 331470645418640. Its totient is φ = 43710414780456.

The previous prime is 131131244341369. The next prime is 131131244341429. The reversal of 131131244341404 is 404143442131131.

131131244341404 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 3 + 1 + 244 + 3 + 4 + 1 + 404 = 666.

131131244341404 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (18).

It is a Harshad number since it is a multiple of its sum of digits (36), and also a Moran number because the ratio is a prime number: 3642534565039 = 131131244341404 / (1 + 3 + 1 + 1 + 3 + 1 + 2 + 4 + 4 + 3 + 4 + 1 + 4 + 0 + 4).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1821267282484 + ... + 1821267282555.

Almost surely, 2^{131131244341404} is an apocalyptic number.

It is an amenable number.

131131244341404 is an abundant number, since it is smaller than the sum of its proper divisors (200339401077236).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131131244341404 is a wasteful number, since it uses less digits than its factorization.

131131244341404 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3642534565049 (or 3642534565044 counting only the distinct ones).

The product of its (nonzero) digits is 55296, while the sum is 36.

Adding to 131131244341404 its reverse (404143442131131), we get a palindrome (535274686472535).

The spelling of 131131244341404 in words is "one hundred thirty-one trillion, one hundred thirty-one billion, two hundred forty-four million, three hundred forty-one thousand, four hundred four".