Base | Representation |
---|---|
bin | 10011000101010000010… |
… | …111110000111011101100 |
3 | 11122100201200120100202021 |
4 | 103011100113300323230 |
5 | 132441032214313200 |
6 | 2442224205435524 |
7 | 163511366160124 |
oct | 23052027607354 |
9 | 4570650510667 |
10 | 1311313432300 |
11 | 466141279343 |
12 | 19218426bba4 |
13 | 9686bc43791 |
14 | 47679d27c84 |
15 | 2419c27841a |
hex | 131505f0eec |
1311313432300 has 72 divisors (see below), whose sum is σ = 2937628424192. Its totient is φ = 507555720000.
The previous prime is 1311313432279. The next prime is 1311313432307. The reversal of 1311313432300 is 32343131131.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is not an unprimeable number, because it can be changed into a prime (1311313432307) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 59456275 + ... + 59478325.
Almost surely, 21311313432300 is an apocalyptic number.
1311313432300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1311313432300 is an abundant number, since it is smaller than the sum of its proper divisors (1626314991892).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311313432300 is a wasteful number, since it uses less digits than its factorization.
1311313432300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41279 (or 41272 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1311313432300 its reverse (32343131131), we get a palindrome (1343656563431).
The spelling of 1311313432300 in words is "one trillion, three hundred eleven billion, three hundred thirteen million, four hundred thirty-two thousand, three hundred".
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