1311314220432 has 60 divisors (see below), whose sum is σ = 3739101183324. Its totient is φ = 428857478400.

The previous prime is 1311314220389. The next prime is 1311314220451. The reversal of 1311314220432 is 2340224131131.

1311314220432 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 3 + 1 + 4 + 220 + 432 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 391280274576 + 920033945856 = 625524^2 + 959184^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1311314220396 and 1311314220405.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 85901319 + ... + 85916582.

Almost surely, 2^{1311314220432} is an apocalyptic number.

1311314220432 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1311314220432 is an abundant number, since it is smaller than the sum of its proper divisors (2427786962892).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311314220432 is a wasteful number, since it uses less digits than its factorization.

1311314220432 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 171817968 (or 171817959 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 1311314220432 its reverse (2340224131131), we get a palindrome (3651538351563).

The spelling of 1311314220432 in words is "one trillion, three hundred eleven billion, three hundred fourteen million, two hundred twenty thousand, four hundred thirty-two".