Base | Representation |
---|---|
bin | 1011111011010010011110… |
… | …1000101001000110010010 |
3 | 1201102121110110111110022022 |
4 | 2332310213220221012102 |
5 | 3204321313212321320 |
6 | 43520042044011442 |
7 | 2522253215632361 |
oct | 276644750510622 |
9 | 51377413443268 |
10 | 13113200120210 |
11 | 41a6305675553 |
12 | 1579514230b82 |
13 | 741753166778 |
14 | 33497a2257d8 |
15 | 17b1876a3325 |
hex | bed27a29192 |
13113200120210 has 32 divisors (see below), whose sum is σ = 24418089446400. Its totient is φ = 5064324018880.
The previous prime is 13113200120179. The next prime is 13113200120227. The reversal of 13113200120210 is 1202100231131.
13113200120210 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×131132001202103 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18747551 + ... + 19434429.
It is an arithmetic number, because the mean of its divisors is an integer number (763065295200).
Almost surely, 213113200120210 is an apocalyptic number.
13113200120210 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13113200120210 is a deficient number, since it is larger than the sum of its proper divisors (11304889326190).
13113200120210 is a wasteful number, since it uses less digits than its factorization.
13113200120210 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 752746.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 13113200120210 its reverse (1202100231131), we get a palindrome (14315300351341).
The spelling of 13113200120210 in words is "thirteen trillion, one hundred thirteen billion, two hundred million, one hundred twenty thousand, two hundred ten".
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