Base | Representation |
---|---|
bin | 111101000100000010… |
… | …0111011001010000011 |
3 | 110112110211000100222022 |
4 | 1322020010323022003 |
5 | 4122024243324024 |
6 | 140124034032055 |
7 | 12321400463243 |
oct | 1721004731203 |
9 | 415424010868 |
10 | 131132011139 |
11 | 50681668928 |
12 | 214b7a1862b |
13 | c49a5829cc |
14 | 64bd97bb23 |
15 | 362741e35e |
hex | 1e8813b283 |
131132011139 has 2 divisors, whose sum is σ = 131132011140. Its totient is φ = 131132011138.
The previous prime is 131132011103. The next prime is 131132011141. The reversal of 131132011139 is 931110231131.
It is a strong prime.
It is an emirp because it is prime and its reverse (931110231131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131132011139 is a prime.
Together with 131132011141, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (131132011159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65566005569 + 65566005570.
It is an arithmetic number, because the mean of its divisors is an integer number (65566005570).
Almost surely, 2131132011139 is an apocalyptic number.
131132011139 is a deficient number, since it is larger than the sum of its proper divisors (1).
131132011139 is an equidigital number, since it uses as much as digits as its factorization.
131132011139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 26.
The spelling of 131132011139 in words is "one hundred thirty-one billion, one hundred thirty-two million, eleven thousand, one hundred thirty-nine".
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