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13113202103077 is a prime number
BaseRepresentation
bin1011111011010010011111…
…0000001101001100100101
31201102121110121020012021211
42332310213300031030211
53204321314214244302
643520042154311421
72522253241531336
oct276644760151445
951377417205254
1013113202103077
1141a63067aa28a
121579514a28571
137417536ac16b
1433497a5c028d
1517b187945ad7
hexbed27c0d325

13113202103077 has 2 divisors, whose sum is σ = 13113202103078. Its totient is φ = 13113202103076.

The previous prime is 13113202103039. The next prime is 13113202103203. The reversal of 13113202103077 is 77030120231131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13016502249921 + 96699853156 = 3607839^2 + 310966^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13113202103077 is a prime.

It is a super-2 number, since 2×131132021030772 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13113202103977) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556601051538 + 6556601051539.

It is an arithmetic number, because the mean of its divisors is an integer number (6556601051539).

Almost surely, 213113202103077 is an apocalyptic number.

It is an amenable number.

13113202103077 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113202103077 is an equidigital number, since it uses as much as digits as its factorization.

13113202103077 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5292, while the sum is 31.

The spelling of 13113202103077 in words is "thirteen trillion, one hundred thirteen billion, two hundred two million, one hundred three thousand, seventy-seven".