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13113203344 = 24819575209
BaseRepresentation
bin11000011011001101…
…11001101010010000
31020211212210202020221
430031212321222100
5203323440001334
610005113242424
7642646250353
oct141546715220
936755722227
1013113203344
11561a07483a
12265b703414
13130c989127
148c57d629a
1551b3638b4
hex30d9b9a90

13113203344 has 10 divisors (see below), whose sum is σ = 25406831510. Its totient is φ = 6556601664.

The previous prime is 13113203333. The next prime is 13113203347. The reversal of 13113203344 is 44330231131.

It can be written as a sum of positive squares in only one way, i.e., 8941593600 + 4171609744 = 94560^2 + 64588^2 .

It is a super-2 number, since 2×131132033442 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13113203347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 409787589 + ... + 409787620.

It is an arithmetic number, because the mean of its divisors is an integer number (2540683151).

Almost surely, 213113203344 is an apocalyptic number.

It is an amenable number.

13113203344 is a deficient number, since it is larger than the sum of its proper divisors (12293628166).

13113203344 is an equidigital number, since it uses as much as digits as its factorization.

13113203344 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 819575217 (or 819575211 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13113203344 its reverse (44330231131), we get a palindrome (57443434475).

The spelling of 13113203344 in words is "thirteen billion, one hundred thirteen million, two hundred three thousand, three hundred forty-four".

Divisors: 1 2 4 8 16 819575209 1639150418 3278300836 6556601672 13113203344