13113210161 has 2 divisors, whose sum is σ = 13113210162. Its totient is φ = 13113210160.

The previous prime is 13113210109. The next prime is 13113210163. The reversal of 13113210161 is 16101231131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9254440000 + 3858770161 = 96200^2 + 62119^2 .

It is a cyclic number.

It is not a de Polignac number, because 13113210161 - 2¹⁴ = 13113193777 is a prime.

It is a Sophie Germain prime.

Together with 13113210163, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (13113210163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556605080 + 6556605081.

It is an arithmetic number, because the mean of its divisors is an integer number (6556605081).

Almost surely, 2^13113210161 is an apocalyptic number.

It is an amenable number.

13113210161 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113210161 is an equidigital number, since it uses as much as digits as its factorization.

13113210161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 13113210161 its reverse (16101231131), we get a palindrome (29214441292).

The spelling of 13113210161 in words is "thirteen billion, one hundred thirteen million, two hundred ten thousand, one hundred sixty-one".