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13113211014851 is a prime number
BaseRepresentation
bin1011111011010010100001…
…0010001100111011000011
31201102121111012222221221112
42332310220102030323003
53204321324004433401
643520043113313535
72522253410346233
oct276645022147303
951377435887845
1013113211014851
1141a6310836892
121579517a058ab
137417554ac5bc
1433497b85dcc3
1517b1886063bb
hexbed2848cec3

13113211014851 has 2 divisors, whose sum is σ = 13113211014852. Its totient is φ = 13113211014850.

The previous prime is 13113211014847. The next prime is 13113211014881. The reversal of 13113211014851 is 15841011231131.

13113211014851 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13113211014851 - 22 = 13113211014847 is a prime.

It is not a weakly prime, because it can be changed into another prime (13113211014881) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556605507425 + 6556605507426.

It is an arithmetic number, because the mean of its divisors is an integer number (6556605507426).

Almost surely, 213113211014851 is an apocalyptic number.

13113211014851 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113211014851 is an equidigital number, since it uses as much as digits as its factorization.

13113211014851 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 32.

Adding to 13113211014851 its reverse (15841011231131), we get a palindrome (28954222245982).

The spelling of 13113211014851 in words is "thirteen trillion, one hundred thirteen billion, two hundred eleven million, fourteen thousand, eight hundred fifty-one".