Base | Representation |
---|---|
bin | 10011000101010000111… |
… | …000110111110101000101 |
3 | 11122100202021220022002202 |
4 | 103011100320313311011 |
5 | 132441041430030201 |
6 | 2442225115444245 |
7 | 163511533015256 |
oct | 23052070676505 |
9 | 4570667808082 |
10 | 1311322111301 |
11 | 466146166a74 |
12 | 192187156685 |
13 | 96870991c97 |
14 | 4767b146b2d |
15 | 2419cddec6b |
hex | 13150e37d45 |
1311322111301 has 2 divisors, whose sum is σ = 1311322111302. Its totient is φ = 1311322111300.
The previous prime is 1311322111181. The next prime is 1311322111349. The reversal of 1311322111301 is 1031112231131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 845665999201 + 465656112100 = 919601^2 + 682390^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311322111301 - 234 = 1294142242117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311322111381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655661055650 + 655661055651.
It is an arithmetic number, because the mean of its divisors is an integer number (655661055651).
Almost surely, 21311322111301 is an apocalyptic number.
It is an amenable number.
1311322111301 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311322111301 is an equidigital number, since it uses as much as digits as its factorization.
1311322111301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 1311322111301 its reverse (1031112231131), we get a palindrome (2342434342432).
The spelling of 1311322111301 in words is "one trillion, three hundred eleven billion, three hundred twenty-two million, one hundred eleven thousand, three hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •