Base | Representation |
---|---|
bin | 10011000101010001001… |
… | …001110100010011110011 |
3 | 11122100202121020222102101 |
4 | 103011101021310103303 |
5 | 132441044044201311 |
6 | 2442225355001231 |
7 | 163511615535634 |
oct | 23052111642363 |
9 | 4570677228371 |
10 | 1311326553331 |
11 | 466148720373 |
12 | 192188739217 |
13 | 96871888ac2 |
14 | 4767b98188b |
15 | 2419d4baec1 |
hex | 131512744f3 |
1311326553331 has 2 divisors, whose sum is σ = 1311326553332. Its totient is φ = 1311326553330.
The previous prime is 1311326553259. The next prime is 1311326553337. The reversal of 1311326553331 is 1333556231131.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (1333556231131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1311326553331 - 233 = 1302736618739 is a prime.
It is a super-2 number, since 2×13113265533312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1311326553337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655663276665 + 655663276666.
It is an arithmetic number, because the mean of its divisors is an integer number (655663276666).
Almost surely, 21311326553331 is an apocalyptic number.
1311326553331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311326553331 is an equidigital number, since it uses as much as digits as its factorization.
1311326553331 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 72900, while the sum is 37.
The spelling of 1311326553331 in words is "one trillion, three hundred eleven billion, three hundred twenty-six million, five hundred fifty-three thousand, three hundred thirty-one".
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