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13113321233 is a prime number
BaseRepresentation
bin11000011011001110…
…10110011100010001
31020211220000201222012
430031213112130101
5203324002234413
610005115552305
7642650251145
oct141547263421
936756021865
1013113321233
11561a145371
12265b75b695
13130c9ca99c
148c5827225
1551b3887a8
hex30d9d6711

13113321233 has 2 divisors, whose sum is σ = 13113321234. Its totient is φ = 13113321232.

The previous prime is 13113321227. The next prime is 13113321301. The reversal of 13113321233 is 33212331131.

13113321233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11497843984 + 1615477249 = 107228^2 + 40193^2 .

It is a cyclic number.

It is not a de Polignac number, because 13113321233 - 24 = 13113321217 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13113321199 and 13113321208.

It is not a weakly prime, because it can be changed into another prime (13113321203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556660616 + 6556660617.

It is an arithmetic number, because the mean of its divisors is an integer number (6556660617).

Almost surely, 213113321233 is an apocalyptic number.

It is an amenable number.

13113321233 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113321233 is an equidigital number, since it uses as much as digits as its factorization.

13113321233 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 972, while the sum is 23.

Adding to 13113321233 its reverse (33212331131), we get a palindrome (46325652364).

The spelling of 13113321233 in words is "thirteen billion, one hundred thirteen million, three hundred twenty-one thousand, two hundred thirty-three".