Base | Representation |
---|---|
bin | 1011111011010010111110… |
… | …0000001011111000001111 |
3 | 1201102121210122212210111021 |
4 | 2332310233200023320033 |
5 | 3204322101010333403 |
6 | 43520103121135011 |
7 | 2522256410625544 |
oct | 276645740137017 |
9 | 51377718783437 |
10 | 13113332121103 |
11 | 41a63731337a5 |
12 | 157955048a467 |
13 | 741774602bc6 |
14 | 33498d986bcb |
15 | 17b1940798bd |
hex | bed2f80be0f |
13113332121103 has 8 divisors (see below), whose sum is σ = 13340772857120. Its totient is φ = 12886293581280.
The previous prime is 13113332121101. The next prime is 13113332121107. The reversal of 13113332121103 is 30112123331131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13113332121103 - 21 = 13113332121101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13113332121101) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 100483275 + ... + 100613692.
It is an arithmetic number, because the mean of its divisors is an integer number (1667596607140).
Almost surely, 213113332121103 is an apocalyptic number.
13113332121103 is a deficient number, since it is larger than the sum of its proper divisors (227440736017).
13113332121103 is a wasteful number, since it uses less digits than its factorization.
13113332121103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 201098097.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 13113332121103 its reverse (30112123331131), we get a palindrome (43225455452234).
The spelling of 13113332121103 in words is "thirteen trillion, one hundred thirteen billion, three hundred thirty-two million, one hundred twenty-one thousand, one hundred three".
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