Base | Representation |
---|---|
bin | 10011000101010001100… |
… | …111011111001011111010 |
3 | 11122100210010220010120000 |
4 | 103011101213133023322 |
5 | 132441103042044010 |
6 | 2442230233413430 |
7 | 163512041621505 |
oct | 23052147371372 |
9 | 4570703803500 |
10 | 1311334331130 |
11 | 4661520529aa |
12 | 19218b26a276 |
13 | 96873380055 |
14 | 4767ca0813c |
15 | 2419e0057c0 |
hex | 131519df2fa |
1311334331130 has 80 divisors (see below), whose sum is σ = 3527349451560. Its totient is φ = 349558530048.
The previous prime is 1311334331117. The next prime is 1311334331159. The reversal of 1311334331130 is 311334331131.
1311334331130 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 3 + 343 + 311 + 3 + 0 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 684198628569 + 627135702561 = 827163^2 + 791919^2 .
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 1311334331094 and 1311334331103.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 1877062 + ... + 2479118.
Almost surely, 21311334331130 is an apocalyptic number.
1311334331130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1311334331130 is an abundant number, since it is smaller than the sum of its proper divisors (2216015120430).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311334331130 is a wasteful number, since it uses less digits than its factorization.
1311334331130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 604765 (or 604756 counting only the distinct ones).
The product of its (nonzero) digits is 2916, while the sum is 27.
Adding to 1311334331130 its reverse (311334331131), we get a palindrome (1622668662261).
Subtracting from 1311334331130 its reverse (311334331131), we obtain a palindrome (999999999999).
The spelling of 1311334331130 in words is "one trillion, three hundred eleven billion, three hundred thirty-four million, three hundred thirty-one thousand, one hundred thirty".
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