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1311334424400 = 24352711131091687
BaseRepresentation
bin10011000101010001100…
…111110101111101010000
311122100210011001212111110
4103011101213311331100
5132441103103040100
62442230235413320
7163512042460440
oct23052147657520
94570704055443
101311334424400
11466152106a90
1219218b2b4240
13968733b3640
144767ca30120
152419e023250
hex131519f5f50

1311334424400 has 480 divisors, whose sum is σ = 5640027015168. Its totient is φ = 251524454400.

The previous prime is 1311334424399. The next prime is 1311334424423. The reversal of 1311334424400 is 44244331131.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 655357 + ... + 1747043.

Almost surely, 21311334424400 is an apocalyptic number.

1311334424400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1311334424400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2820013507584).

1311334424400 is an abundant number, since it is smaller than the sum of its proper divisors (4328692590768).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311334424400 is a wasteful number, since it uses less digits than its factorization.

1311334424400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1091739 (or 1091728 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 30.

Adding to 1311334424400 its reverse (44244331131), we get a palindrome (1355578755531).

The spelling of 1311334424400 in words is "one trillion, three hundred eleven billion, three hundred thirty-four million, four hundred twenty-four thousand, four hundred".