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131134035 = 35197199223
BaseRepresentation
bin1111101000011…
…11001001010011
3100010202022002010
413310033021103
5232032242120
621002354003
73151422654
oct764171123
9303668063
10131134035
1168026a3a
1237abb903
1321224a06
14135b752b
15b7a47e0
hex7d0f253

131134035 has 32 divisors (see below), whose sum is σ = 212889600. Its totient is φ = 68923008.

The previous prime is 131134033. The next prime is 131134051. The reversal of 131134035 is 530431131.

It is not a de Polignac number, because 131134035 - 21 = 131134033 is a prime.

It is a super-2 number, since 2×1311340352 = 34392270270762450, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (131134033) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 587934 + ... + 588156.

It is an arithmetic number, because the mean of its divisors is an integer number (6652800).

Almost surely, 2131134035 is an apocalyptic number.

131134035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

131134035 is a deficient number, since it is larger than the sum of its proper divisors (81755565).

131134035 is a wasteful number, since it uses less digits than its factorization.

131134035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 627.

The product of its (nonzero) digits is 540, while the sum is 21.

The square root of 131134035 is about 11451.3769914364. The cubic root of 131134035 is about 508.0484626818.

Adding to 131134035 its reverse (530431131), we get a palindrome (661565166).

The spelling of 131134035 in words is "one hundred thirty-one million, one hundred thirty-four thousand, thirty-five".

Divisors: 1 3 5 15 197 199 223 591 597 669 985 995 1115 2955 2985 3345 39203 43931 44377 117609 131793 133131 196015 219655 221885 588045 658965 665655 8742269 26226807 43711345 131134035