Base | Representation |
---|---|
bin | 111101000100000110… |
… | …1011110011100001011 |
3 | 110112110222020020222012 |
4 | 1322020031132130023 |
5 | 4122030332042221 |
6 | 140124154050135 |
7 | 12321425520602 |
oct | 1721015363413 |
9 | 415428206865 |
10 | 131134252811 |
11 | 5068295a051 |
12 | 214b871994b |
13 | c49ab89143 |
14 | 64bdda2a39 |
15 | 362771365b |
hex | 1e8835e70b |
131134252811 has 2 divisors, whose sum is σ = 131134252812. Its totient is φ = 131134252810.
The previous prime is 131134252787. The next prime is 131134252853. The reversal of 131134252811 is 118252431131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131134252811 - 26 = 131134252747 is a prime.
It is a super-2 number, since 2×1311342528112 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131134252891) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65567126405 + 65567126406.
It is an arithmetic number, because the mean of its divisors is an integer number (65567126406).
Almost surely, 2131134252811 is an apocalyptic number.
131134252811 is a deficient number, since it is larger than the sum of its proper divisors (1).
131134252811 is an equidigital number, since it uses as much as digits as its factorization.
131134252811 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5760, while the sum is 32.
Adding to 131134252811 its reverse (118252431131), we get a palindrome (249386683942).
The spelling of 131134252811 in words is "one hundred thirty-one billion, one hundred thirty-four million, two hundred fifty-two thousand, eight hundred eleven".
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